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Limiting Friction

Two blocks A ...

Question

Two blocks A and B, having masses $m_{1}$ and $m_{2}$ respectively, are placed in contact on a smooth horizontal surface. A force F is applied horizontally on A. The contact force between A and B is

\frac{m_{1}}{m_{2}} F

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\frac{m_{2}}{m_{1}} F

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\frac{m_{1} F}{{m_{1} + m}_{2}}

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\frac{m_{2} F}{{m_{1} + m}_{2}}

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Solution

The correct option is D $\frac{m_{2} F}{{m_{1} + m}_{2}}$
Since the system moves as a whole with the same acceleration of both the masses, let the acceleration be 'a'.
then F= $(m_{1} + m_{2}) a$

let F' be the normal force on $m_{2}$
then F' = $m_{2} a$ or F'= $\frac{m_{2} F}{m_{1} + m_{2}}$

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Two blocks A and B, having masses m1 and m2 respectively, are placed in contact on a smooth horizontal surface. A force F is applied horizontally on A. The contact force between A and B is

The correct option is D m2Fm1+m2Since the system moves as a whole with the same acceleration of both the masses, let the acceleration be 'a'.then F=(m1+m2)alet F' be the normal force on m2then F' = m2a or F'=m2Fm1+m2

Two blocks A and B, having masses $m_{1}$ and $m_{2}$ respectively, are placed in contact on a smooth horizontal surface. A force F is applied horizontally on A. The contact force between A and B is

The correct option is D $\frac{m_{2} F}{{m_{1} + m}_{2}}$
Since the system moves as a whole with the same acceleration of both the masses, let the acceleration be 'a'.
then F= $(m_{1} + m_{2}) a$

let F' be the normal force on $m_{2}$
then F' = $m_{2} a$ or F'= $\frac{m_{2} F}{m_{1} + m_{2}}$