Two blocks $A$ and $B$ having masses $m_{1}$ and $m_{2}$ respectively, placed in contact on a smooth horizontal surface. A force $F$ is applied horizontally on $A$ . What is acceleration and contact force between $A$ and $B$ ?

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Solution

From Newton's 2nd law, $F = (m_{1} + m_{2}) a \Rightarrow a = \frac{F}{(m_{1} + m_{2})}$
contact force between A and B will be , $N = m_{2} a = \frac{m_{2} F}{(m_{1} + m_{2})}$

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Two blocks A and B having masses m1 and m2 respectively, placed in contact on a smooth horizontal surface. A force F is applied horizontally on A. What is acceleration and contact force between A and B?

From Newton's 2nd law, F=(m1+m2)a⇒a=F(m1+m2)contact force between A and B will be ,N=m2a=m2F(m1+m2)

Two blocks $A$ and $B$ having masses $m_{1}$ and $m_{2}$ respectively, placed in contact on a smooth horizontal surface. A force $F$ is applied horizontally on $A$ . What is acceleration and contact force between $A$ and $B$ ?

From Newton's 2nd law, $F = (m_{1} + m_{2}) a \Rightarrow a = \frac{F}{(m_{1} + m_{2})}$
contact force between A and B will be , $N = m_{2} a = \frac{m_{2} F}{(m_{1} + m_{2})}$