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Question

Two blocks are in contact on a frictionless table. One has mass m and the other 2 m. A force F is applied on 2 m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of the force of contact between the two blocks will be :



292973_deab071b50c7498b845b0f272abce13b.png



A
Same
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B
1 : 2
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C
2 : 1
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D
1 : 3
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Solution

The correct option is(B):1 : 2

If F is the applied force then acceleration of the system is

F2m+m=F3m

Now when we are applying the force from the left,the force applied on the block m is

Fm+2m×m=F3

This will be the force in the contact from left.

When we apply the force from the right from onthe block will be

Fm+2m×2m=2F3

this will be the forceon the contact from right side.

So the ratio is F3 :2F3 =1:2



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