Two blocks are kept in contact as shown in figure. Find.
1) forces exerted by surfaces (floor and wall) on blocks.
2) contact force between two blocks.

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Solution

$N_{F} =$ Normal force by Floor
$N_{W} =$ Normal force by wall
$N_{B} =$ Normal force by block of $10 k g$
Contact Force
blocks are in rest so Net Force on each $= 0$
$N_{F} - 10 g = 0 \Rightarrow N_{F} = 10 g = 100 N$ by Floor on $10 k g$
$N_{B} - 100 = 0 - - - - (1) \Rightarrow N_{B} = 100 N$ contact Force
$N_{F} - [20 g + S o n s 30^{o}) = 0$ or $N_{F} - (200 + 25 \sqrt{3})$
$\Rightarrow N_{F} = 200 + 25 \sqrt{3}$ by floor on $20 k g$
$N_{W} + 50 sin 30 = N_{B}$ , Put $N_{B} = 100$
We get $N_{W} = 100 - 50 sin 30 = 75 N$
By wall on $20 k g$

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