Two blocks are kept in contact as shown in the figure.
Find the value of normal force exerted by the vertical wall on 20 kg block. (Assume all surfaces are smooth)
(Take g=10 m/s2)
N1=10g=100 N ... (1)
N2=100 N ... (2)
FBD of 20 kg block
N2=50sin30∘+N3
∴N3=N2−50sin30∘=100−25=75 N ... (3)