Two blocks are kept in contact as shown in the figure.
Find the value of normal force exerted by the vertical wall on 20kg block. (Assume all surfaces are smooth) (Takeg=10m/s2)
A
200N
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B
100N
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C
25N
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D
75N
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Solution
The correct option is D75N
FBD of 10kg block N1=10g=100N ... (1) N2=100N ... (2)
FBD of 20kg block N2=50sin30∘+N3 ∴N3=100−25=75N ... (3)