Two blocks of mass 4 kg and 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be

5 N

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4 N

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2 N

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None of the above

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Solution

The correct option is C
2 N

$L e t m_{1} = 6 k g, m_{2} = 4 k g a n d F = 5 N (g i v e n)$ Force on the lighter mass $= \frac{m_{2} \times F}{m_{1} + m_{2}} = \frac{4 \times 5}{6 + 4} = 2 N$

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Two blocks of mass 4 kg and 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be

The correct option is C 2 N Let m1=6kg,m2=4kg and F=5N(given) Force on the lighter mass =m2×Fm1+m2=4×56+4=2N

The correct option is C
2 N

$L e t m_{1} = 6 k g, m_{2} = 4 k g a n d F = 5 N (g i v e n)$ Force on the lighter mass $= \frac{m_{2} \times F}{m_{1} + m_{2}} = \frac{4 \times 5}{6 + 4} = 2 N$