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Question

Two blocks of masses M1=4kg and M2=6kg are connected by a string of negligible mass passing over a frictionless pulley as shown in the figure. The coefficient of friction between the block M1 and the horizontal surface is 0.4. When the system is released, the masses M1 and M2 start accelerating. What additional mass m should be placed over M1 so that the masses (M1+m) slide with a uniform speed?
1019726_72f5b159e0654e55834401974f420565.png

A
12 kg
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B
1kg
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C
10 kg
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D
8kg
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Solution

The correct option is B 12 kg


For uniform motion of mass M2-

T=M2g

For uniform motion of (M1+m)-

T=f

And, fμN=μ(M1+m)g

μ(M1+m)gM2g

mM2μM1

m60.44

m11kg

Hence, m=12kg

962390_1019726_ans_a9c10f7bf5644c7ab1470e3ce1baf3c1.png

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