Question

Two blocks of masses $m$ and $M$ are placed on a horizontal frictionless table connected by light spring as shown in the figure. Mass $M$ is pulled to the right with a force $F$. If the acceleration of mass $m$ is $a$, the acceleration of mass $M$ will be

• A. $\frac{(F-ma)}{M}$
• B. $\frac{(F+ma)}{M}$
• C. $\frac{F}{M}$
• D. $\frac{ma}{M}$

Answer 1

The correct option is A $\frac{(F-ma)}{M}$

For the block with mass $m$, the force experienced is the spring force.

$\therefore$ Spring force $=$ Mass $\times$ acceleration = $ma$

For block with mass $M$, forces are spring force and the external $F$

$\therefore$ acceleration $=\frac{totalforce}{mass}=\frac{F-ma}{M}$