Question

Two bodies $A$ and $B$ each of mass $m$ are fixed together by a massless spring $A$ force $F$ acts on the mass $B$ as shown in figure. At the instant shown, a body $A$ has an acceleration a, what is the acceleration of $B$?

• A. $(\frac{F}{m}-a)$
• B. $F-T$
• C. $(a-\frac{F}{m})$
• D. $a$

Answer 1

The correct option is A $(\frac{F}{m}-a)$

from the formula of force,$[\frac{F}{m}–a=0]$

body $A$ has acceleration $a$.

Let acceleration of $B$ be $A$

Thus relation can be given as,

$mA=F–T$

where $T=ma$

$mA=F–ma$

$A=\frac{F–ma}{m}\Rightarrow \frac{F}{m}-a$