Question

Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9g / $c{m}^3$is

• A.
• B.
• C. 3
• D. 5

Answer 1

The correct option is C

3

Apparent weight = $V(p-\sigma )g=\frac{m}{p}(p-\sigma )$ where mass of the body, density of the body and $\sigma$= density of water If two bodies are in equilibrium then their apparent weight must be equal. $\therefore \frac{m_1}{p_1}(p_1-\sigma )g=\frac{m_2}{p_2}(p_2-\sigma )g\Rightarrow \frac{36}{9}(9-1)=\frac{48}{p_2}(p_2-1)g$.. By soliving we get $p_2$ = 3