Question

Two bodies are in equilibrium when suspended in water from the arms of balance. The mass of one body is $$36\ g$$ and its density is $$9\ g/ cm^{3}$$. If the mass of the other is $$48\ g$$, its density in $$g/ cm^{3}$$ is:

A
43
B
32
C
3
D
5

Solution

The correct option is C $$3$$Resultant force on both of them must be same.For the body of mass $$36gram$$     $${ F }_{ \left( Net \right) }=36\times 10-36\cfrac { { \rho }_{ w } }{ 9 } \times 10=36\times 10\left[ \cfrac { 8 }{ 9 } \right] =320N\\ 320=480-\cfrac { 48\times 1\times 10 }{ \rho } \\ \cfrac { 480 }{ \rho } =160\\ \rho =\cfrac { 480 }{ 160 } =3$$Physics

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