Question

Two bodies are in equilibrium when suspended in water from the arms of balance. The mass of one body is $36g$ and its density is $9g/c{m}^3$. If the mass of the other is $48g$, its density in $g/c{m}^3$ is:

• A. $\frac{4}{3}$
• B. $\frac{3}{2}$
• C. $3$
• D. $5$

Answer 1

The correct option is C $3$

Resultant force on both of them must be same.

For the body of mass $36gram$

$F_{\left(Net\right)}=36\times 10-36\frac{{\rho }_w}{9}\times 10=36\times 10\left[\frac{8}{9}\right]=320N320=480-\frac{48\times 1\times 10}{\rho }\frac{480}{\rho }=160\rho =\frac{480}{160}=3$