Two bodies are projected with the same velocity- If one is projected at an angle of 30- and the other at an angle of 60- to the horizontal- the ratio of the maximum heights reached is

The correct option is B 1 : 3 H_1/H_2=sin^2θ_1/sin^2θ_2=sin^230^∘/sin^260^∘=1/3 ...

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Standard XII

Physics

Projectile Time, Height and Range

Two bodies ar...

Question

Two bodies are projected with the same velocity. If one is projected at an angle of $30^{\circ}$ and the other at an angle of $60^{\circ}$ to the horizontal, the ratio of the maximum heights reached is

3 : 1

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1 : 3

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1 : 2

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2 : 1

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Solution

The correct option is B 1 : 3
$\frac{H_{1}}{H_{2}} = \frac{s i n^{2} θ_{1}}{s i n^{2} θ_{2}} = \frac{s i n^{2} 30^{\circ}}{s i n^{2} 60^{\circ}} = \frac{1}{3}$

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Two bodies are projected with the same velocity. If one is projected at an angle of 30∘ and the other at an angle of 60∘ to the horizontal, the ratio of the maximum heights reached is

The correct option is B 1 : 3 H1H2=sin2θ1sin2θ2=sin230∘sin260∘=13

Two bodies are projected with the same velocity. If one is projected at an angle of $30^{\circ}$ and the other at an angle of $60^{\circ}$ to the horizontal, the ratio of the maximum heights reached is

The correct option is B 1 : 3
$\frac{H_{1}}{H_{2}} = \frac{s i n^{2} θ_{1}}{s i n^{2} θ_{2}} = \frac{s i n^{2} 30^{\circ}}{s i n^{2} 60^{\circ}} = \frac{1}{3}$