Question

Two bodies are thrown at angle $\alpha$ and $(90-\alpha )$ with the horizontal. What is the ratio of their horizontal range?

• A. 1:3
• B. 2:3
• C. 1:1
• D. 4:1

Answer 1

The correct option is C 1:1

We know that for projection speed $u$ and projection angle $\theta$ the range is calculated as $R=u^{2}Sin2\theta /g$

For $\theta =\alpha$ we get $R_1=u^{2}Sin2\alpha /g$

For $\theta =90-\alpha$ we get $R_2=u^{2}Sin2(90-\alpha )/g=u^{2}Sin(180-2\alpha )/g=u^{2}Sin2\alpha /g$

So ratio is $R_1/R_2=1$