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Question

Two bodies are thrown at angle θ and (90θ) from the same point with same velocity 25 ms1. If the difference between their maximum height is 15 m, find the respective maximum heights.
(g=10 ms2)

A
H1=858 m and H2=1758 m
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B
H1=1858 m and H2=658 m
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C
H1=654 m and H2=1358 m
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D
H1=1254 m and H2=658 m
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Solution

The correct option is B H1=1858 m and H2=658 m
Let H1 and H2 be the maximum heights of the bodies thrown at angles θ and 90θ respectively.
H1=u2sin2θ2g and H2=u2sin2(90θ)2g=u2cos2θ2g
H1+H2=u22g
H1+H2=25220=1254 m.......(i)
According to queston
H1H2=15 m........(ii)
By using equ. (i) and (ii), we get
H1=1858 m and H2=658 m

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