Two bodies are thrown at angle θ and (90−θ) from the same point with same velocity 25ms−1. If the difference between their maximum height is 15m, find the respective maximum heights. (g=10ms−2)
A
H1=858m and H2=1758m
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B
H1=1858m and H2=658m
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C
H1=654m and H2=1358m
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D
H1=1254m and H2=658m
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Solution
The correct option is BH1=1858m and H2=658m Let H1 and H2 be the maximum heights of the bodies thrown at angles θ and 90−θ respectively. H1=u2sin2θ2gandH2=u2sin2(90−θ)2g=u2cos2θ2g ⇒H1+H2=u22g H1+H2=25220=1254m.......(i)
According to queston H1−H2=15m........(ii)
By using equ. (i) and (ii), we get H1=1858m and H2=658m