Question

Two bodies of different masses are dropped from heights of $2\text{m}$ respectively, then the ratio of the time taken by them is

• A. $1:4$
• B. $1:1$
• C. $1:2$
• D. $1:3$

Answer 1

The correct option is B $1:1$

From second equation of motion
$S=ut+\frac{1}{2}a{t}^2$, where, $s=$ displacement and $t=$ time
Given, $u=0$
But here we are considering $s$ as height $h$.
and, $h\propto t^2$
$\therefore \sqrt{\frac{h_1}{h_2}}=\frac{t_1}{t_2}$
Since, both the bodies are dropped from the same height, $\Rightarrow h_1=h_2$
$\Rightarrow t_1:t_2=1:1$