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Question

Two bodies of masses m1 and m2 are acted upon by a constant force F for a time t. They start from rest and acquire kinetic energies E1 and E2 respectively. Then E1E2 is

A
m1m2
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B
m2m1
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C
1
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D
m1m2m1+m2
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Solution

The correct option is B m2m1
Bodies of mass m1 and m2 acted on by force F (say) for time t. Acceleration in mass m1= Fm1
Acceleration in mass m2= Fm2
Velocity acquired during this time for mass m1
v1=Fm1t
Velocity acquired during this time for mass m2
v2=Fm2t
Ratio of kinetic energy acquired
E1E2=12m1v2112m2v22
E1E2=m1×(Fm1t)2m2×(Fm2t)2
E1E2=m2m1

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