Question

Two candidates attempt to solve a quadratic equation of the $a{x}^2+bx+c=0$ One starts with a wrong value of $b$ and find the roots to be $2$ and $6$. The other starts with the wrong values of $c$ and find the roots to be $+2,-9$. The correct roots of the equation are

Answer 1

a and c are true so that product of the roots are $2\times 6$ i.e. 12 Again a and b are true so the sum of the roots is -7
$\therefore$ The roots are -3 and -4