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Parallel and Series Combination of Capacitors

Two capacitor...

Question

Two capacitors $C_{1}$ and $C_{2}$ are connected in parallel. Assume that $C_{1} < C_{2}$ . The equivalent capacitance of this arrangement is $C$ , where

C < C_{1} / 2

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C_{1} < C < C_{1}

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C_{1} < C < C_{2}

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C_{2} < C < 2 C_{2}

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Solution

The correct option is D $C_{2} < C < 2 C_{2}$
We have, parallel capacitance, $C_{P} = C_{1} + C_{2}$
Given $C_{2} > C_{1}$
$⟹ 2 C_{2} > C_{P} > (C_{1} + C_{2}) > C_{2} > C_{1}$
Hence option (a), (b) and (c) are wrong.

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