Question

Two capacitors each having capacitance $3\mu \text{F}$ and breakdown voltage $6\text{V}$ are joined together in parallel connection. The breakdown voltage of the combination will be :

• A. $12\text{V}$
• B. $3\text{V}$
• C. $18\text{V}$
• D. $6\text{V}$

Answer 1

The correct option is D $6\text{V}$

In a parallel combination, the potential difference across each capacitor will be equal. In this case, both the capacitors are identical and have the same breakdown voltage$\left(6\text{V}\right)$

Therefore if the applied voltage exceeds $6\text{V}$, both the capacitors will get damaged/break-down. So, the breakdown voltage of their combination will be $6\text{V}$.

Hence, option (d) is the correct answer.

Key concept- Breakdown voltage of two identical capacitors in parallel connection will be the same as that of individual breakdown voltage of the capacitors.