Question

Two capacitors of $400\mu \text{F}$ and $600\mu \text{F}$ in parallel are connected to a battery of $100\text{V}.$ Find the ratio of charge stored in $400\mu \text{F}$ to charge stored in $600\mu \text{F}$.

• A. $\frac{2}{3}$
  
• B. $\frac{1}{3}$
• C. $\frac{1}{2}$
• D. $\frac{3}{2}$

Answer 1

The correct option is A $\frac{2}{3}$


The capacitors are in parallel, which implies that the potential difference across both the capacitors will be $100\text{V}.$

Now the charge on $400\mu \text{F}$:

$Q_1=\left(400\mu \text{F}\right)\times \left(100\text{V}\right)=40000\mu C$

And the charge on $600\mu \text{F}$:

$Q_2=\left(600\mu \text{F}\right)\times \left(100\text{V}\right)=60000\mu C$

So, the ratio of the cahrges:

$\frac{Q_1}{Q_2}=\frac{40000}{60000}=\frac{2}{3}$

Hence, option (a) is the correct answer.

Key concept: Charge on capacitors in parallel combination in a circuit.