Two cars $A$ and $B$ are moving on a straight road. The car $A$ is moving with speed $60$ miles per hour while the car $B$ is moving with speed $30$ miles per hour. Given that mass of both cars are same. The ratio of the $A$ car's kinetic energy to the $B$ car's kinetic energy is:

4 : 1

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2 : 1

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1 : 1

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1 : 2

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1 : 4

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Solution

The correct option is A $4 : 1$
Kinetic energy is proportional to the square of the speed (KE = $\frac{1}{2} m v^{2})$ , so the car with twice the speed that is car A, will have four times the kinetic energy of car B.Hence their ratio is $4 : 1$ .

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Two cars A and B are moving on a straight road. The car A is moving with speed 60 miles per hour while the car B is moving with speed 30 miles per hour. Given that mass of both cars are same. The ratio of the A car's kinetic energy to the B car's kinetic energy is:

The correct option is A 4:1Kinetic energy is proportional to the square of the speed (KE = 12mv2), so the car with twice the speed that is car A, will have four times the kinetic energy of car B.Hence their ratio is 4:1.

Two cars $A$ and $B$ are moving on a straight road. The car $A$ is moving with speed $60$ miles per hour while the car $B$ is moving with speed $30$ miles per hour. Given that mass of both cars are same. The ratio of the $A$ car's kinetic energy to the $B$ car's kinetic energy is:

The correct option is A $4 : 1$
Kinetic energy is proportional to the square of the speed (KE = $\frac{1}{2} m v^{2})$ , so the car with twice the speed that is car A, will have four times the kinetic energy of car B.Hence their ratio is $4 : 1$ .