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Standard VII

Physics

Displacement

Two cars A an...

Question

Two cars A and B move such that car A moving with a uniform velocity of $15 m s^{- 1}$ overtakes car B starting from rest with an acceleration of $3 m s^{- 2}$ . After how much time do they meet again?

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15s

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\sqrt{3}

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10s

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Solution

The correct option is D 10s
Let us assume that the car A and B meet after a time $^{'} t^{'}$
Distance travelled by A in that time is $v t$
$= 15 t$
Distance travelled by B is
$s = u t + \frac{1}{2} a t^{2}$
$s = \frac{3 t^{2}}{2}$
$\frac{3 t^{2}}{2} = 15 t$
$t = 0, 10 s$
$t = 0$ is trivial . Therefore, at $t = 10 s$ , both the cars meet.

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Two cars A and B move such that car A moving with a uniform velocity of 15 ms−1 overtakes car B starting from rest with an acceleration of 3 ms−2. After how much time do they meet again?

The correct option is D 10sLet us assume that the car A and B meet after a time ′t′Distance travelled by A in that time is vt=15tDistance travelled by B iss=ut+12at2s=3t223t22=15tt=0,10st=0 is trivial . Therefore, at t=10s, both the cars meet.

Two cars A and B move such that car A moving with a uniform velocity of $15 m s^{- 1}$ overtakes car B starting from rest with an acceleration of $3 m s^{- 2}$ . After how much time do they meet again?