Question

Two cars A and B start from the same starting point. A is starting from rest and moving with constant acceleration $2$ $m/s^2$ and car B is starting with a constant velocity $40$ m/s. After what time both cars will meet each other?

Answer 1

Let distance covered by A be $S1$
Let distance covered by B be $S2$

B will catch A when $S1=S2$

$S=ut+\frac{1}{2}\times a\times t^2$

$40t+(\frac{1}{2}\times 0\times t^2)=0t+1/2\times 2\times t^2$

$40t=t^2$

$40=t$