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Question

Two cars are moving. A along east with 10 ms−1. At any instant it is 1500 m away from the crossing. B at the same instant is 1800 m away from the crossing and is moving towards the crossing along north direction with 15 ms−1. When do they come closest?


A
109.3s
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B
129.2s
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C
119.3s
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D
99.3s
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Solution

The correct option is A 129.2s
x2=(150010t)2+(180015t)2, for x to be minimum, its first derivative should be zero.
Thus, dxdt=0
=20(150010t)30(180015t)
or t=129.23s

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