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Derivation of Position-Time Relation by Graphical Method

Two cars movi...

Question

Two cars moving in the same direction on the straight road with constant speeds. Initial separation between them is 100m and the rear car is moving with 20m/s while the front car with 10m/s. The rear will cross the front in

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Solution

Let A : rear car
B: front car
$S_{B A} = 100$
$v_{B A} = 20 - 10 = 10$
$t = \frac{S_{B A}}{v_{B A}}$
$t = 10 s$

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