Question

Two cars P and Q start side by side from rest at the same instant and in the same direction. P accelerates uniformly at 4$m/s^2$ for 10 seconds and then moves with uniform velocity. Q moves with uniform acceleration 3 $m/s^2$.Find the distance between them 30 seconds after start.

Answer 1

Given,

$p=4m/s^2{t}_1=10s,q=3m/s^2,t_2=30s$

So, the distance for p is $\frac{1}{2}a{t}^2=\frac{1}{2}\times 4\times {10}^2=200m$

Then the velocity constant after $10s$ $0+4\times 10=40m/s$

So total distance for Q is:

Since $u=0$

$s=ut+\frac{1}{2}a{t}^2=\frac{1}{2}3\times {30}^2=1350m$