You visited us 1 times! Enjoying our articles? Unlock Full Access!

More about Q=CV

Two cells, tw...

Question

Two cells, two resistors and two capacitors are connected as shown in figure. The charge on $2 μ F$ capacitor is :

30 μ C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 μ C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 μ C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

48 μ C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $30 μ C$
When the capacitor is fully charged , the current only flow through the resistors in this circuit.

As the two capacitors are charged by two different emf so they connected in series so charge of them is equal .i.e, q (say).

Apply Kirchhoff's law,

for loop AEHDA: $18 = (1 + 5) i_{1} \Rightarrow i_{1} = 3 A$

for loop BCGFB: $15 = (2 + 4) i_{2} \Rightarrow i_{2} = 2.5 A$

for loop ABCDA: $18 + 15 = q / 3 + 2 i_{2} + q / 2 + 1 i_{1}$

or $33 = (5 / 6) q + 2 (2.5) + 1 (3) = (5 / 6) q + 8$

or $q = 25 \times (6 / 5) = 30 μ C$

Suggest Corrections

Similar questions

Q. Two capacitors of

2 μ F

and

3 μ F

are charged to

150 V

and

120 V

respectively. The plates of capacitor are connected as shown in the figure. An uncharged capacitor of capacity

1.5 μ F

is connected to the free end of the wires as shown. Then:

Two capacitors of capacity $C_{1}$ and $C_{2}$ are connected as shown in the figure. Now the switch is closed. Calculate the charge on each capacitor.

Q. Two capacitors of

2 μ F

and

3 μ F

are charged to

150 V

and

120 V

respectively. The plates of capacitor are connected as shown in the figure. An uncharged capacitor of capacity

1.5 μ F

falls to the free end of the wire. Then :

Q. Two capacitors of

2 μ F

and

3 μ F

are charged to

150 v o l t

and

120 v o l t

respectively. The plates of capacitor are connected as shown in the figure. A discharged capacitor of capacity

1.5 μ F

falls to the free ends of the wire. Then :

Q. Two capacitors

C_{1} = 2 μ F

and

C_{2} = 6 μ F

in series, are connected in parallel to a third capacitor

C_{3} = 4 μ F

. This arrangement is then connected to a battery of e.m.f.=2 V, as shown in figure. The energy lost by the battery in charging the capacitors is :

Join BYJU'S Learning Program

Two cells, two resistors and two capacitors are connected as shown in figure. The charge on 2μF capacitor is :

Two cells, two resistors and two capacitors are connected as shown in figure. The charge on $2 μ F$ capacitor is :