Question

Two charged particles are placed at a distance $1.0cm$ apart. What is the minimum possible magnitude of the electric force acting on each charge?

• A. $23\times {10}^{-24}N$
• B. $2.3\times {10}^{-24}N$
• C. $2.3\times {10}^{-23}N$
• D. $0$

Answer 1

The correct option is B $2.3\times {10}^{-24}N$

Electrostatic repulsion $=F=\frac{1}{4\pi {ϵ}_o}\frac{q_1{q}_2}{(.01{)}^2}$

force will be minimum when $q_1=q_2=$ minimum unit of charge $={ϵ}_o=1.6\times {10}^{-19}C$

minimum force $=2.3\times {10}^{-24}N$