Question

Two charged particles are separated at a distance of 1 cm.what is the minimum possible magnitude of the electric force acting on each particle ?

Answer 1

Dear student

F = KQq/r²

hence , magnitude of force depends upon products of magnitude of charges
and distance between them .
but here distance between charge particle is fixed so,

only depends upon product of magnitude of charge .

we know smallest charge = 1.6 × 10^-19C
of electrons exist in nature .

so, if we choose both charge particle " electrons " then force will be minimum.

now,

F = Ke²/r²

= 9× 10^9 × (1.6 × 10^-19)²/(1/100)²

= 9 × 2.56 × 10^(-29+4 )N

= 23.04 × 10^-25 N

= 2.304 × 10^-24 N

Hope you understand it.