Question

Two charged thin infinite plane sheets of uniform surface charge density ${\sigma }_{+}$ and ${\sigma }_{-}$, where $|{\sigma }_{+}|$ > $|{\sigma }_{-}|$, intersect at a right angle. Which of the following best represents the electric field lines for this system?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

The electric field produced due to a uniformly charged infinite plane is,

$E=\frac{\sigma }{2{\epsilon }_0}=\text{constant}$

So, option $\left(2\right)$ and $\left(4\right)$ are wrong.

$\because |{\sigma }_{+}|$ > $|{\sigma }_{-}|$

Hence, its field along $y-$ direction will be bigger than field of $-ve$ charge density ${\sigma }_{-}$in $x-$ direction.


<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.