Two charges placed in air repel each other by a force of $10^{- 4} N$ . When oil is introduced between the charges, the force becomes $2.5 \times 10^{- 5} N$ . The dielectric constant of oil is:

2.5

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0.25

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2.0

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4.0

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Solution

The correct option is D $4.0$
We know that, $F_{m e d}$ = $\frac{F_{v a c}}{K}$
where,
$F_{m e d}$ = Force in a given medium = 2.5 x 10⁻⁵ N
$F_{v a c}$ = Force in vacuum/air = 10⁻⁴ N
K = dielectric constant of the given medium.

Using the above formula, dielectric constant of oil,
K = $\frac{F_{v a c}}{F_{m e d}}$ = $\frac{10^{- 4}}{2.5 \times 10^{- 5}}$ = 4.0

Hence, option D is correct.

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Two charges placed in air repel each other by a force of 10−4N. When oil is introduced between the charges, the force becomes 2.5×10−5N. The dielectric constant of oil is:

Two charges placed in air repel each other by a force of $10^{- 4} N$ . When oil is introduced between the charges, the force becomes $2.5 \times 10^{- 5} N$ . The dielectric constant of oil is: