Two charges +Q and −2Q are located at points A and B on a horizontal line as shown in the figure. The electric field is zero at a point which is located at a finite distance :
A
on the perpendicular bisector of AB
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B
left of A on the line
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C
between A and B on the line
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D
right of B on the line
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Solution
The correct option is A left of A on the line The point must be located at the left of A. E1 is electric field by Q will be toward left and E2 by -2Q will be toward right.