Two charges Q & −Q are kept at some distance, so that electric field at the mid point is →E. Find the force on Q due to the field of −Q. (charges are isolated)
A
Q→E4
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B
4Q→E
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C
Q→E8
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D
Q→E2
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Solution
The correct option is CQ→E8
Let E+ be electric field at mid point due to positive charge, E− be electric field at mid point due to negative charge
Let distance between the charges be r.
The electric field at the midpoint, →E=→E++→E− =kQ(r/2)2^i+kQ(r/2)2^i=8kQr2^i
[taking positive x axis in rightward direction]
At position Q, the field due to −Q is →EQ=kQr2^i=→E8