Two charges $\sqrt{3} C$ and q C are placed at (2, 0) and (0.2). The direction of intensity of electric field at (2, 2) makes an angle $30^{\circ}$ with y–axis then q is:

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\sqrt{3} C

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Solution

The correct option is A 1C
$T a n 30 = \frac{E_{x}}{E_{y}} \frac{1}{\sqrt{3}} = \frac{\frac{1}{4 π ϵ_{0}} (\frac{q}{2^{2}})}{\frac{1}{4 π ϵ_{0}} (\frac{\sqrt{3}}{2^{2}})}; \frac{1}{\sqrt{3}} = \frac{q}{\sqrt{3}}$
q=1c

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