Two children Goutham and Pavani are fighting for coins. Finally Goutham won and took a coin from Pavani's pocket which has four different coins (a 1 rupee coin, a 2 rupee coin, a 5 rupee coin, and a 10 rupee coin). What is the probability that Goutham took out a 5 rupee coin?

$\frac{5}{10}$

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$\frac{1}{4}$

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$\frac{5}{4}$

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$\frac{5}{18}$

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Solution

The correct option is B
$\frac{1}{4}$

Probability = $\frac{N o . o f f a v o u r a b l e o u t c o m e s}{T o t a l n o . o f o u t c o m e s}$

As there is only one 5 rupee coin and there are 4 different outcomes, P(E)= $\frac{1}{4}$

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Two kids Goutham and Pavani are fighting for coins. Finally, Goutham won and stole a coin from Pavani's pocket which has four different coins ( a 1 rupee coin, a 2 rupee coin, a 5 rupee coin, a 10 rupee coin). What are the total number of possible outcomes when Goutham tried to steal a coin?

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Two children Goutham and Pavani are fighting for coins. Finally Goutham won and took a coin from Pavani's pocket which has four different coins (a 1 rupee coin, a 2 rupee coin, a 5 rupee coin, and a 10 rupee coin). What is the probability that Goutham took out a 5 rupee coin?

The correct option is B 14 Probability = No. of favourable outcomes Total no. of outcomes As there is only one 5 rupee coin and there are 4 different outcomes, P(E)=14

The correct option is B
$\frac{1}{4}$

Probability = $\frac{N o . o f f a v o u r a b l e o u t c o m e s}{T o t a l n o . o f o u t c o m e s}$

As there is only one 5 rupee coin and there are 4 different outcomes, P(E)= $\frac{1}{4}$