Two chords AB and CD intersect at point O inside the circle. If OA = 5 cm, OB = 6 cm and OC = 3 cm, then the value of CD is .

12 cm

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3 cm

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10 cm

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13 cm

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Solution

The correct option is D 13 cm
When two chords intersect each other in a circle, the product of the chord segments will be equal.
So, $O A \times O B = O D \times O C$
$5 \times 6 = O D \times 3$
$O D = 10 c m$
$C D = O C + O D = 3 + 10 = 13 c m$

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