Question

Two chords $AB$ and $CD$ of a circle intersect each other (externally) at $P$ outside the circle. If $AP=10$ cm, $CP=6$ cm and $PD=5$ cm, find $PB$

Answer 1

Here the chords $AB$ and $CD$ intersect each other at $P$ outside the circle.

$PA\times PB=PC\times PD$

$10\times PB=6\times 5$

$PB=\frac{30}{10}=3$cm