Two cities 150km apart. Electric power is sent one city to another city through copper wire. The fall potential per km is 8 volt and the average resistance per km is 0.5 ohm. The power loss in the wire is?

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Solution

$S o f o r 150 K M t h e t o t a l p o t e n t i a l d r o p i s = V = 150 \times 8 = 1200 V n o w p o w e r l o s s P = I \times V = \frac{V^{2}}{R} = \frac{1200^{2}}{(150 \times 0.5)} = 19200 J$

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Two cities 150km apart. Electric power is sent one city to another city through copper wire. The fall potential per km is 8 volt and the average resistance per km is 0.5 ohm. The power loss in the wire is?

So for 150 KM the total potential drop is= V=150 ×8 =1200 Vnow power loss P=I×V =V2R=12002(150 ×0.5)=19200 J

$S o f o r 150 K M t h e t o t a l p o t e n t i a l d r o p i s = V = 150 \times 8 = 1200 V n o w p o w e r l o s s P = I \times V = \frac{V^{2}}{R} = \frac{1200^{2}}{(150 \times 0.5)} = 19200 J$