You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Avogadro's Law & Gay Lussac's Law

Two closed ve...

Question

Two closed vessel $A$ and $B$ of equal volume containing air at pressure $P_{1}$ and temperature $T_{1}$ are connected to each other through a narrow open tube. If the temperature of one is now maintained at $T_{1}$ and other at $T_{2}$ (where $T_{1} > T_{2}$ ) then that what will be the final pressure?

\frac{T_{1}}{2 P_{1} T_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 P_{1} T_{2}}{T_{1} + T_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2 P_{1} T_{2}}{T_{1} - T_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 P_{1}}{T_{1} + T_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{2 P_{1} T_{2}}{T_{1} + T_{2}}$
Let the final pressure of the containers be $P$ .
For connecting vessels,
$Initial moles of vessel (A + B) = Final moles of vessel (A + B) \frac{P_{1} V}{R T_{1}} + \frac{P_{1} V}{R T_{1}} = \frac{P V}{R T_{1}} + \frac{P V}{R T_{2}} \frac{P_{1}}{T_{1}} + \frac{P_{1}}{T_{1}} = \frac{P}{T_{1}} + \frac{P}{T_{2}} \frac{2 P_{1}}{T_{1}} = P (\frac{T_{1} + T_{2}}{T_{1} T_{2}}) ∴ P = \frac{2 P_{1} T_{2}}{T_{1} + T_{2}}$

Suggest Corrections

Similar questions

Q. Two closed vessel

A

and

B

of equal volume containing air at pressure

P_{1}

and temperature

T_{1}

are connected to each other through a narrow open tube. If the temperature of one is now maintained at

T_{1}

and other at

T_{2}

(where

T_{1} > T_{2}

) then that what will be the final pressure?

Q. Two closed vessel

A

and

B

of equal volume containing air at pressure

P_{1}

and temperature

T_{1}

are connected to each other through a narrow open tube. If the temperature of one is now maintained at

T_{1}

and other at

T_{2}

(where

T_{1} > T_{2}

) then that what will be the final pressure?

Q. Two closed vessels of equal volume containing air at pressure

P_{1}

and temperature

T_{1}

are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at

T_{1}

and that in the other at

T_{2}

, what will be the pressure in the vessels

Q. Two closed vessels of an equal volume containing air at pressure

P_{1}

and temperature

T_{1}

are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at

T_{1}

and that in the other at

T_{2}

, what will be the pressure in the vessels?

Two closed vessels of equal volume containing air at pressure p₁ and temperature T₁ are connected to temperature in one of the vessels is now maintained at T₁ and that in the other at T₂. What will be the pressure in the vessels?

Join BYJU'S Learning Program

Explore more

Avogadro's Law & Gay Lussac's Law

Standard XII Chemistry

Join BYJU'S Learning Program

Two closed vessel A and B of equal volume containing air at pressure P1 and temperature T1 are connected to each other through a narrow open tube. If the temperature of one is now maintained at T1 and other at T2 (where T1>T2) then that what will be the final pressure?

The correct option is B 2P1T2T1+T2Let the final pressure of the containers be P. For connecting vessels, Initial moles of vessel (A+B) = Final moles of vessel (A+B)P1VRT1+P1VRT1=PVRT1+PVRT2P1T1+P1T1=PT1+PT22P1T1=P(T1+T2T1T2)∴ P=2P1T2T1+T2