wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two closed vessels of equal volume contain air at pressure 100 kPa and temperature 250 K and are connected through a narrow tube. If one of the vessels is now maintained at 250 K and the other at 300 K, what will be the pressure in the vessels?

A
100 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
210 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
109 kPa
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
120 kPa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 109 kPa
Let the initial pressure, volume and temperature in each vessel be P0 (=100 kPa),V0 and T0 (=250 K). Let the number of moles in each vessel be n.


At final state, both vessels have same pressure P and let the number of moles be n1, n2 respectively .
Then, n1+n2=2n [Total moles will be same]
Using ideal gas equation,
PV0RT0+PV0RT1=2P0V0RT0
PT0+PT1=2P0T0
P=2P0T0×T0×T1T0+T1
=2×100250×250×300550
P=109 kPa

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon