Question

Two coil have a mutual inductance 0.005 H.The current changes in first coil according to equation $I=I_{0}sin\omega twhere{I}_0=2Aand\omega =100\pi rad/sec.$ The maximum value of emf in second coil is

• A. $4\pi$
• B. $3\pi$
• C. $2\pi$
• D. $\pi$

Answer 1

Answer: (D)

$\pi$

$e=M\frac{di}{dt}=0.005\times \frac{d}{dt}\left(i_{0}sin\omega t\right)$

$=0.005i_0\omega cos\omega t=e_{0}cos\omega t$

$\therefore e_{max}=0.005\times 2\times 100\pi =\pi$