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Question

Two coils A and B have mutual inductance 2×102 henry. If the current in the primary is i=5sin(10πt), then the maximum value of e.m.f. induced in coil B is :

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Solution

Given,

M=2×102H

Current in primary coil A,

i=5sin(10πt)

The emf induced in coil B,

e=Mdidt

e=M×5×10πcos(10πt)

e=2×102×50πcos(10πt)

The maximum value of emf induced in coil B is

emax=π

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