Question

Two coins are tossed 400 times and we get

two heads:112 limes; one head: 160 times; 0 head: 128 limes.

When two coins are tossed at random, what is the prohability of getting

(i) 2 heads? (ii) 1 head? (iii) 0 head?

Answer 1

ANSWER:
T otal number of tosses = 400
Number of times 2 heads appear = 112
Number of times 1 head appears = 160
Number of times 0 head appears = 128
In a random toss of two coins, let E 1 , E 2 , E 3 be the events of getting 2 heads, 1 head and 0 head,
respectively. Then,
(i) P(getting 2 heads) = P(E 1 ) = Number of times 2 heads appear/Total number of trials = 112/400 = 0.28
(ii) P( getting 1 head) = P(E 2 ) = Number of times 1 head appears/Total number of trials = 160/400 = 0.4
(iii) P( getting 0 head) = P(E 3 ) = Number of times 0 head appears/Total number of trials = 128/400 = 0.32