Question

Two coins are tossed $600$ times and we get two heads $138$ times, one head $192$ times and no heads $270$ times. What is the probability of getting exactly one tail

• A. $\frac{192}{600}$
• B. $\frac{138}{600}$
• C. $\frac{462}{600}$
• D. $\frac{408}{600}$

Answer 1

The correct option is A $\frac{192}{600}$

Two coins are tossed $600$ times.

Therefore, $n\left(S\right)=600$.

Let $A$ be the event of getting two heads, $n\left(A\right)=138$.

Let $B$ be the event of getting one head, $n\left(B\right)=192$.

Let $C$ be the event of getting no heads, $n\left(C\right)=270$.

We have to find the probability of getting exactly one tail.

Probability of getting exactly one tail is same as probability of getting exactly one head.

Therefore, probability of getting exactly one tail is $\frac{192}{600}$.