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Question

Two coins are tossed simultaneously 1000 times with the following frequencies at different outcomes

OverheadFrequency2 heads3501 head310No head340

if these two coins are tossed again, find the probability of getting

(i) at least 1 head

(ii) at most one head

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Solution

Two coins are tossed simultaneously 1000 times.

Total number of trails =1000

Let A: The event of getting at least 1 head.

B: The event of getting at most 1 head.

Number of trials of getting at least 1 head = the sum of the number of trials of getting 1 head and the number of trials of getting 2 heads.

Number of trails of getting at least 1 head =310+350=660

Number of trials of getting at most 1 head = the sum of the number of trials of getting 0 head and the number of trials of getting 1 head.

Number of trails of getting at most 1 head =340+310=650

(i) P(A)=Number of trails of getting at least 1 headTotal number of trails=6601000=0.66

(ii) P(B)=Number of trials of getting at most 1 headTotal number of trails=6501000=0.65


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