The correct option is C 0.5
Let the no. of times 'No Tail' appeared = x.
No. of times '1 Tail' appeared = 2x.
No. of times '2 Tails' appeared = 3x.
x + 2x + 3x = 360
⇒x=60
No. of times 2 Tail appeared = 3 x 60 = 180
Then, P(Getting 2 Tails)=180360=0.5