Two coins are tossed simultaneously for 200 times and the number of heads are recorded as follows-Number of heads Frequency065185250What is the probability of 1 head appearing-

The correct option is C 0.425We know, for an event E, P(E) = nbsp;Number of trials in which the event happened/Total number of trials Here, the event E is 1 ...

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Standard IX

Mathematics

Coin Tossing Experiment

Two coins are...

Question

Two coins are tossed simultaneously for $200$ times and the number of heads are recorded as follows:
$\begin{matrix} Number of heads & Frequency 0 & 65 1 & 85 2 & 50 \end{matrix}$
What is the probability of $1$ head appearing?

0.4

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0.5

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0.425

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0.75

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Solution

The correct option is C 0.425
We know, for an event $E$ ,
$P (E) = \frac{Number of trials in which the event happened}{Total number of trials}$
Here, the event $E$ is $1$ head appearing, which happens $85$ times.
Given, total number of trials(or tosses) is $200$ .
Therefore,
$P (E) = \frac{85}{200} = 0.425$

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Two coins are tossed simultaneously for 200 times and the number of heads are recorded as follows: Number of heads Frequency065185250What is the probability of 1 head appearing?

The correct option is C 0.425We know, for an event E, P(E)=Number of trials in which the event happenedTotal number of trialsHere, the event E is 1 head appearing, which happens 85 times. Given, total number of trials(or tosses) is 200. Therefore,P(E)=85200=0.425

Two coins are tossed simultaneously for $200$ times and the number of heads are recorded as follows:
$\begin{matrix} Number of heads & Frequency 0 & 65 1 & 85 2 & 50 \end{matrix}$
What is the probability of $1$ head appearing?