Question

Two coins are tossed simultaneously for $200$ times and the number of heads are recorded as follows:
$\begin{array}{cc}\text{Number of heads}& \text{Frequency}\\ 0& 65\\ 1& 85\\ 2& 50\end{array}$
What is the probability of $1$ head appearing?

• A. 0.4
• B. 0.5
• C. 0.425
• D. 0.75

Answer 1

The correct option is C 0.425

We know, for an event $E$,
$P\left(E\right)=\frac{\text{Number of trials in which the event happened}}{\text{Total number of trials}}$
Here, the event $E$ is $1$ head appearing, which happens $85$ times.
Given, total number of trials(or tosses) is $200$.
Therefore,
$P\left(E\right)=\frac{85}{200}=0.425$