Question

Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times the number ‘No Tail’ appeared and the number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. What is the probability of getting ‘Two tails’?

• A. $\frac{3}{2}$
• B. $\frac{1}{2}$
• C. $\frac{3}{4}$
• D. $\frac{5}{2}$

Answer 1

The correct option is

C

$\frac{1}{2}$

Given,

Total number of outcomes = Sample space = 360

Now, assume that the number of times ‘No Tail’ appeared to be “x”

So, the number of times ‘2 Tails’ appeared = 3x (from the question)

Also, the number of times ‘1 Tail’ appeared =2x (from the question)

As the total outcomes = 360,

x + 2x + 3x = 360

=> 6x = 360

Or, x = 60

∴ P(getting two tails) =$\frac{(3\times 60)}{360}$ = $\frac{1}{2}$